Answered By: Bryan Kasik
Last Updated: Jan 14, 2020     Views: 480

You can access LinkedIn Learning with UVA-level access and a Netbadge prompt using the link on this page, which also has links to tutorials and FAQs that can answer many questions you may have about it: https://www.library.virginia.edu/lynda/

Please bear in mind that, like all UVA library-accessible resources, you always need to access them through a UVA library website for it to know you are a UVA user. If you just go directly to the resource website, it won't recognize your UVA credentials and will just treat you as a public or first-time user.

When you log into LinkedIn Learning via Netbadge, it creates a new LinkedIn Learning account for you under the University of Virginia enterprise license. This is not the same thing as a traditional LinkedIn account that you may or may not have. You are not required to create a traditional LinkedIn account as a part of LinkedIn Learning. They will ask you (repeatedly) whether you want to connect your LinkedIn Learning account to your regular LinkedIn account, but you are not required to do so.

If you do not use the link above or the link available on our databases page here, you may encounter errors. When you go directly to the homepage or to a LinkedIn Learning course, you’ll see a message asking you to pay for access. There’s a sign-in button at the top right, but that takes you to the individual subscription login page. There is also a “Sign in to your organizational account” link there, at which point you’ll need to enter your UVa email address in the xxx0x@virginia.edu format, and you’ll be taken in through NetBadge.

For existing lynda.com bookmarks, if the saved lynda.com URL contains “org=virginia.edu” (e.g. https://www.lynda.com/R-tutorials/Up-Running-R/120612-2.html?org=virginia.edu) then it should redirect correctly to the LinkedIn Learning platform.

If you have any issues with your LinkedIn Learning account, please contact lib-ejournals@virginia.edu directly as they are in touch with LinkedIn.